We played BackdoorCTF and we won the second place....

We played BSides Mumbai CTF 2022 last week and we got the third. This is the write-up on the challenges we solved....

We played TSJ CTF last weekend and we won! This is the writeups of our challenges...

Because there are not many Crypto listed in the "Stock Market", our Cryptotrader Cryptanalyst Mystiz joined us for bounty hunting in Web as well, and we got all Web challenges done this time....

Because there are not many Crypto listed in the "Stock Market", I decided to join our Webb-expert Web-expert Ozetta for bounty hunting in web, and we got all web challenges done this time. The writeup of the web challenges can be found here....

We played the annual Gold Bug puzzle hosted by the DEFCON Crypto and Privacy Village - and we won! Although we were unable to ace the challenge before the game ends, we managed to solve the remaining challenge afterwards. We will be covering all of them in this walkthrough....

We are united to play 3kCTF-2021 and result in the second place. In this blog post, we will walk through our solutions on the challenges solved....

We played Cyber Apocalypse 2021 and I have attempted several crypto challenges. I'll include the challenges Wii Phit and Hyper Metroid in this writeup....

Lost in Your Eyes is a reverse engineering challenge in DiceCTF 2021 with ten solves (334 points). We are given a binary which takes an input and outputs either :) or :(. If you win a smiley face on the remote server, you are additionally given the flag....

TetCTF is the first CTF I have played in 2021. I recalled from last year that they have cool challenges. This year, there are three crypto challenges. In particular, unevaluated is the hardest among them. Although I did not solve them, I dug into rabbit holes and had a lot of struggle, uh, fun. Challenge Summary There is a 128-bit prime $p$. Define $\cdot: \mathbb{Z}_{p^2}^2\times\mathbb{Z}_{p^2}^2\rightarrow\mathbb{Z}_{p^2}^2$ by \[(x_1, y_1)\cdot(x_2, y_2) := \left(\left(x_1x_2-y_1y_2\right)\ \text{mod}\ p^2, \left(x_1y_2+y_1x_2\right)\ \text{mod}\ p^2\right),\]...